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Question

Two miscible liquids of densities 1.2 gm/cc and 1.4 gm/cc are mixed with a proportion ratio of their
volumes equal to 3:5. Then, the density of the resulting liquid  in gm/cc upto two decimals will be 


Solution

Let, the volume of first liquid be V1=3V Volume of second liquid V2=5V
Given:
ρ1=1.2gmcm3;
ρ2=1.4gmcm3
Mass of first liquid :- m1=ρ1v1=3.6 V
Mass of second liquid :- m2=ρ2v2=7 V
So, Density of resulting liquid :-
ρmixture=mtotalVtotal=m1+m2v1+v2
=3.6V+7V3V+5V=10.6V8V=1.325

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