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Question

Two mole of an ideal gas (Cp,m=52R) is heated from 300 K to 600 K at constant pressure. The change in entropy of the gas (ΔS) is:

A
32Rln2
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B
32Rln2
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C
5Rln2
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D
52Rln2
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Solution

The correct option is B 5Rln2
Solution:- (C) 5Rln2
ΔS=nCPlnT2T1+nRlnP1P2
Pressure is constant,
ΔS=nCPlnT2T1
Given:-
n=2 moles
CP=52R
T2=600K
T1=300K
ΔS=2×52R×ln600300
ΔS=5Rln2
Hence the change in entropy of the gas is 5Rln2.

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