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Question

Two moles of NH3 are introduced into one litre flask in which it dissociates at high temperature as follows:
2NH3(g)N2(g)+3H2(g). Determine KC, if at equilibrium 1 mole of NH3 remains.

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Solution

2NH3(g)N2(g)+3H2(g)
200
10.51.5

Now Kc=[N2][H2]3[NH3]2
=[0.5][1.5]3[1.0]2
Kc=1.6875 mol2/l2

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