CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two motorboats, which can move with velocities 4.0 m/s and 6.0 m/s relative to water are going up-stream. When the faster one overtakes the slower one, a buoy (floating device) is dropped from the slower one. After sometime both the boats turn back simultaneously and move at the same speeds relative to the water as before. Their engines are switched off when they reach the buoy again. If the maximum separation between the boats is 200 m after the buoy is dropped and water flow velocity is 1.5 m/s, find the distance( in metres) travelled by the buoy from the dropping point till the point where the boats meet the buoy again. ___


Open in App
Solution

Let after time t they turn back at C and D respectively.

d = 200 m
x = (4 - 15) t
x + 200 = (6 - 1.5) t
t = 100 s, x = 250 m
After turning, both boats take another 100 s to meet the buoy. So in total 200 sec, the distance moved by buoy = u × 200 = 1.5 × 200 = 300 m


flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative Motion
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon