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Question

Two opposite angles of a parallelogram are $$100^o$$ each. Find each of the other two opposite angles.


Solution

Given two opposite angles of a parallelogram are $$100^o$$ each
The sum of adjacent angles of a parallelogram $$=180^o$$
Hence,
$$\angle A+\angle B=180^o$$
$$100^o+\angle B=180^o$$
$$\angle B=180^o -100^o$$
We get, 
$$\angle B=80^o$$
We know that 
The opposite angles of a parallelogram are equal
$$\angle D=\angle B=80^o$$
Therefore, th eother opposite angles $$\angle D=\angle B=80^o$$

1755994_1823365_ans_916f3131c5f34047a3d6eb8dc2ff0991.png

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