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Standard XII

Chemistry

Longest Chain Rule

Two organic c...

Question

Two organic compounds (A) and (B) Containing 62.01% C and 10.3% H react with HCN in different manners to produce (C) and (D), respectively. Subsequent hydrolysis of (C) and (D) gives optically active compounds (E) and (F). Both (E) and (F) on decarboxylation give the same compound (G). Identify the compounds (A) to (G).

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Solution

$C = 62.01$
Formula of $(A)$ and $(B)$ is $C_{3} H_{6} O$ The only possible isomers are aldehyde and ketone.
Here, (F") and (G') are not the same. Moreover, (F') is not O.A.

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C=62.01Formula of (A) and (B) is C3H6O The only possible isomers are aldehyde and ketone.Here, (F") and (G') are not the same. Moreover, (F') is not O.A.

$C = 62.01$
Formula of $(A)$ and $(B)$ is $C_{3} H_{6} O$ The only possible isomers are aldehyde and ketone.
Here, (F") and (G') are not the same. Moreover, (F') is not O.A.