Question

# Two particles $$1$$ and $$2$$ are thrown in the directions shown in figure simultaneously with velocities $$5 m/s$$ and $$20 m/s$$. Initially, particle $$1$$ is at height $$20 m$$ from the ground. Taking upwards as the positive direction, find the acceleration of $$1$$ with respect to $$2$$

Solution

## Given :    $$u_1 = -5 m/s$$            $$u_2 = 20 m/s$$Acceleration of 1       $$a_1 = -g$$Acceleration of 2      $$a_2 = -g$$Acceleration of 1 w.r.t 2        $$a_{12} = -g - (-g) = 0$$Physics

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