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Question

Two particles $$1$$ and $$2$$ are thrown in the directions shown in figure simultaneously with velocities $$5 m/s$$ and $$20 m/s$$. Initially, particle $$1$$ is at height $$20 m$$ from the ground. Taking upwards as the positive direction, find the acceleration of $$1$$ with respect to $$2$$

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Solution

Given :    $$u_1  = -5  m/s$$            $$u_2  = 20 m/s$$
Acceleration of 1       $$a_1  = -g$$
Acceleration of 2      $$a_2  = -g$$
Acceleration of 1 w.r.t 2        $$a_{12}  = -g - (-g)  = 0$$

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Physics

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