Two particles A and B are projected simultaneously from the top of two towers as shown in the figure. After what time from their projection will they collide?
A
1sec
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B
2sec
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C
3sec
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D
4sec
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Solution
The correct option is B2sec Taking downward as positive direction. For the particles to collide Relative displacement in y- direction should be '0'. So, (Srel)y=0 and (Srel)x=150 (Srel)x=(urel)xt+12(arel)xt2 150=(45sin37∘+60sin53∘)t(∵(arel)x=0) 150=(27+48)t ⇒t=2sec