Question

# Two particles having charges q1 and q2 when kept at a certain distance, exert force F on each other. If distance is reduced to half, force between them becomes :

A
F2
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B
2F
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C
4F
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D
F4
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Solution

## The correct option is C 4F Answer is C.Coulomb's law describes the magnitude of the electrostatic force between two electric charges. The Coulomb's law formula is given as follows. The force between 2 charges q1 and q2 is given by the formula F=kq1×q2r2. Where, q1: Charge of object 1 q2: Charge of object 2 r: Distance between the two objects F: Force between the two objects. A positive force implies a repulsive interaction, while a negative force implies an attractive interaction k: Coulomb Constant. In this case, the distance between 2 charges is halved. So the new force becomes Fnew=kq1×q2(r2)2=4×k×q1×q2r2=4F. Hence, the force between the charges becomes 4F.

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