Question

Two particles of medium disturbed by the wave propagation are at $x_1=0and{x}_2=1cm$. The respective displacements (in cm) of the particles can be given by the equations: $y_1=2sin3\pi t,y_2=2sin(3\pi t-\frac{\pi }{8})$. The wave velocity is

• A. 16 cm/s
• B. 24 cm/s
• C. 12 cm/s
• D. 8 cm/s

Answer 1

The correct option is B

24 cm/s

$Given\omega =3\pi f=\frac{\omega }{2\pi }=1.5Also\Delta x=1.0cm\Delta \varphi =\frac{2\pi }{\lambda }\Delta x\Rightarrow \frac{\pi }{8}=\frac{2\pi }{\lambda }\times 1\lambda =16cmv=f\lambda =16\times 1.5=24cm/s$