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Question

Two particles with charges q1 and q2 are kept at a certain distance to exert force F on the other. If the distance is reduced to one-fifth, then the force between them is :

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Solution

Let the distance between them be d
Force F=kq1q2d2
F1d2
Si, if the distance between tem is reduced by a factor of 5, force between them gets increased by a factor of 25.
So, new force F=25F

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