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Question

Two persons A and B start from the same location and walked around a square in opposite directions with constant speeds. The square has side 60 m. Speeds of A and B are 4m/s and 2m/s respectively. When will they meet first time?

A
30 sec
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B
40 sec
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C
10 sec
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D
20 sec
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Solution

The correct option is A 40 sec
Given, speed of the persons A and B around the square =4m/s and 2m/s, respectively.
Let the time t, after which they meet each other. So, total distance travelled by the person A and B in time t is equal to the circumference of the square i.e.,
4t+2t=4×60
6t=240
t=40 sec.

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