Two persons A and B start from the same location and walked around a square in opposite directions with constant speeds. The square has side 60m. Speeds of A and B are 4m/s and 2m/s respectively. When will they meet first time?
A
30sec
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B
40sec
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C
10sec
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D
20sec
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Solution
The correct option is A40sec Given, speed of the persons A and B around the square =4m/s and 2m/s, respectively. Let the time t, after which they meet each other. So, total distance travelled by the person A and B in time t is equal to the circumference of the square i.e., 4t+2t=4×60 6t=240 t=40sec.