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Two plane mirrors are inclined to each other such that a ray of light incident on the first mirror $$(M_1)$$ and parallel to the second mirror $$(M_2)$$ is finally reflected from the second mirror $$(M_2)$$ parallel to the first mirror $$(M_1)$$. The angle between the two mirrors will be :


A
90o
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B
45o
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C
75o
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D
60o
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Solution

The correct option is C $$60^o$$

Assuming angles between two mirrors be $$\theta$$ as per geometry, 
sum of angles of $$\Delta$$
$$\lambda1+\lambda2=360-20=180+\theta$$
$$3 \theta = 180^o$$
$$\theta = 60^o$$

1142069_1328982_ans_af72b1e3c702415e928ed43023eb4f6f.png

Physics

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