Question

# Two plane mirrors parallel to each other and an objective O placed between them.Then the distance of the first three images from the mirror $${ M }_{ 2 }$$will be (in cm)

A
5,10,15
B
5,15,30
C
5,25,35
D
5,35,45

Solution

## The correct option is D 5,25,35$$\begin{array}{l}\text { The first image I will be formed by } m_{2} \text { as object is near. } \\\text { at distance 5m inside } M_{2}\end{array}$$$$\begin{array}{l}\text { Now second image I }_{2}\text { will form } 10 \mathrm{~cm} \text { inside } M_{1} \\\text { So distance from } M_{2}=10+15=25 \mathrm{~cm}\end{array}$$$$\begin{array}{l}\text { Now first image Ii acts as object to } M_{1} \text { and forms } \\\text { third image I }_{3} =20 \mathrm{~cm} \text { inside } M_{1} \\\text { So distance from } M_{2}=20+15=35 \mathrm{~cm}\end{array}$$Physics

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