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Question

Two plane mirrors parallel to each other and an objective O placed between them.Then the distance of the first three images from the mirror $${ M }_{ 2 } $$will be (in cm)
1358240_f3ba2dd456fd419394ee348b4189d1b4.png


A
5,10,15
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B
5,15,30
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C
5,25,35
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D
5,35,45
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Solution

The correct option is D 5,25,35
$$\begin{array}{l}\text { The first image I will be formed by } m_{2} \text { as object is near. } \\\text { at distance 5m inside } M_{2}\end{array}$$
$$\begin{array}{l}\text { Now second image I }_{2}\text { will form } 10 \mathrm{~cm} \text { inside } M_{1} \\\text { So distance from } M_{2}=10+15=25 \mathrm{~cm}\end{array}$$
$$\begin{array}{l}\text { Now first image Ii acts as object to } M_{1} \text { and forms } \\\text { third image I }_{3} =20 \mathrm{~cm} \text { inside } M_{1} \\\text { So distance from } M_{2}=20+15=35 \mathrm{~cm}\end{array}$$

Physics

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