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Question

Two point charges Q1=2μC and Q2=1μC are placed as shown. The coordinates of the point P are (2cm,1cm). The electric intensity vector at P subtends an angle θ with the positive X axis. The value of θ is given by:
476494_addf54ad897a49fabfd1d38e12149b5c.png

A
tanθ=1
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B
tanθ=2
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C
tanθ=3
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D
tanθ=4
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Solution

The correct option is A tanθ=2
Given that:
Q1=2 μC ans Q2=1 μC

We know that:
EQd2

E1E2=2μ(2cm)2×(1cm)21μ=12

E2=2E1

As E1 is directed along +ve x-axis and E2 along +ve y-axis, angle made by their resultant E with +ve x-axis is given by tanθ=E2E1=2

512895_476494_ans_eba4dcca768647d886f18df8008e6668.png

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