Two point charges separated by a distance d repel each other with a force of $10 N$ . If the separation between them becomes $d / 2$ , the force of repulsion will be ______.

10 N

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30 N

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40 N

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5 N

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Solution

The correct option is C $40 N$
$F = \frac{q_{1} q_{2}}{4 π ϵ_{o} d^{2}} = 10 N$

Now when distance becomes $\frac{d}{2}$ -

$F^{'} = \frac{q_{1} q_{2}}{4 π ϵ_{o} {(\frac{d}{2})}^{2}}$

$⟹ F^{'} = \frac{4 q_{1} q_{2}}{4 π ϵ_{o} d^{2}} = 4 F = 4 \times 10$

$⟹ F^{'} = 40 N$

Answer-(C)

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Two point charges separated by a distance d repel each other with a force of 10 N. If the separation between them becomes d/2, the force of repulsion will be ______.

The correct option is C 40 NF=q1q24πϵod2=10NNow when distance becomes d2-F′=q1q24πϵo(d2)2⟹F′=4q1q24πϵod2=4F=4×10⟹F′=40NAnswer-(C)

Two point charges separated by a distance d repel each other with a force of $10 N$ . If the separation between them becomes $d / 2$ , the force of repulsion will be ______.

The correct option is C $40 N$
$F = \frac{q_{1} q_{2}}{4 π ϵ_{o} d^{2}} = 10 N$

Now when distance becomes $\frac{d}{2}$ -

$F^{'} = \frac{q_{1} q_{2}}{4 π ϵ_{o} {(\frac{d}{2})}^{2}}$

$⟹ F^{'} = \frac{4 q_{1} q_{2}}{4 π ϵ_{o} d^{2}} = 4 F = 4 \times 10$

$⟹ F^{'} = 40 N$

Answer-(C)