Question

Two resistors, $4\Omega$ and $6\Omega$ are connected in parallel with a $6\text{V}$ battery of negligible resistance. Calculate the current flowing through $4\Omega$ resistor.

• A. $1\text{A}$
• B. $1.5\text{A}$
• C. $2\text{A}$
• D. $2.5\text{A}$

Answer 1

The correct option is B $1.5\text{A}$

Here, the potential difference across the resistor $R_1$ will be equal to $6\text{V}$.

Now, using Ohm's law, we can write,
$i=\frac{V}{R_1}=\frac{6}{4}=1.5\text{A}$