Two resistors of 6 ohm and 9 ohm are connected in series to a 1120 V source. The power dissipated by the 6 ohm resistor is

28400 W

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33450 W

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15000 W

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18000 W

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Solution

The correct option is B $33450 W$
REF.Image.
$i = V_{n e t} / R_{n e t} = \frac{1120}{15}$
= 74.66 A.
Power 6 $Ω = i^{2} R$
$= (74.66)^{2} \times 6$
$= 33450$ watt

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Two resistors of 6 ohm and 9 ohm are connected in series to a 1120 V source. The power dissipated by the 6 ohm resistor is

The correct option is B 33450WREF.Image.i=Vnet/Rnet=112015 = 74.66 A.Power 6 Ω=i2R=(74.66)2×6=33450 watt

The correct option is B $33450 W$
REF.Image.
$i = V_{n e t} / R_{n e t} = \frac{1120}{15}$
= 74.66 A.
Power 6 $Ω = i^{2} R$
$= (74.66)^{2} \times 6$
$= 33450$ watt