Question

Two ropes are respectively $3\frac{3}{4}mand5\frac{1}{2}m$ long.Find the total length of two ropes.

Answer 1

Total length of two ropes$=3\frac{3}{4}+5\frac{1}{2}$

$$\begin{gathered} =\frac{4x3+3}{4}+\frac{2x5+1}{2} \\ =\frac{12+3}{4}+\frac{10+1}{2} \\ =\frac{15}{4}+\frac{11}{2} \\ =\frac{1x15+2x11}{4} \\ =\frac{15+22}{4} \\ =\frac{37}{4} \end{gathered}$$

Hence total length of two ropes is $\frac{37}{4}m$.