Two runners start simultaneously from the same point on a circular $200 m$ track in the same direction. Their speeds are $6.2 m s^{- 1}$ and $5.5 m s^{- 1}$ . How far from the starting point the faster and the slower runner would be side by side again?

150 m

away from the starting point

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170 m

away from the starting point

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120 m

away from the starting point

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n o n e

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Solution

The correct option is D $170 m$ away from the starting point
Let faster overcome slower after time $t$
Velocity of faster relative to slower $= (6.2 - 5.5) = 0.7 m / s$
$⟹ t = \frac{200}{0.7} = 285.714$
Distance covered by faster $= 6.2 \times t = 6.2 \times 285.714 = 1770 = 8 \times 200 + 170$
Thus after making $8$ complete round on circular track faster will overcome slower at $170 m$ away from the starting point

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Two runners start simultaneously from the same point on a circular 200 m track in the same direction. Their speeds are 6.2 ms−1 and 5.5 ms−1. How far from the starting point the faster and the slower runner would be side by side again?

Two runners start simultaneously from the same point on a circular $200 m$ track in the same direction. Their speeds are $6.2 m s^{- 1}$ and $5.5 m s^{- 1}$ . How far from the starting point the faster and the slower runner would be side by side again?