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Question

Two second after projection, a projectile is moving at 30o above the horizontal, after one more second it is moving horizontally. (g=10m/sec2). The angle of projection is :

A
30o
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B
45o
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C
60o
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D
90o
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Solution

The correct option is C 60o

(Refer to Image)
In time interval of 1 sec
Vy=at
=g×1
=10m/s at Q
Vx=Vytan30o
=1013
=103m/s

Between P and R
Vy=at
=10×3
=30m/s
Vx=103m/s

Angle of projection
tanθ=VyVx
=30103
=3

θ=tan1(3)
=60o .

1205073_1102587_ans_b17ec40ad13d428790b8a95f54b239b3.JPG

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