CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two seconds after projection a projectile is travelling in a direction inclined at 30 to the horizontal after one more sec, it is travelling horizontally, the magnitude and direction of its velocity are


A

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B


Let in 2 sec body reaches upto point A and after one more sec upto point B.

Total time of ascent for a body is given 3 sec i.e. t=u sin θg=3

u sin θ=10×3=30 .............(i)

Horizontal component of velocity remains always constant

u cos θ=vcos30 ..........(ii)

For vertical upward motion between point O and A

v sin 30=u sin θg×2 [Using v=ugtv sin 30=3020 [As u sin θ=30]

Substituting this value in equation (ii) u coa θ=20 cos 30=103......(iii)

From equation (i) and (iii) u=203and θ=60


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Falling Balls in Disguise
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon