1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

# Two ships are sailing in the sea on the two sides of a lighthouse. The angle of elevation of the top of the lighthouse is observed from the ships are 30∘ and 45∘ respectively. If the lighthouse is 100 m high, the distance between the two ships is:

A

173 m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
B

200m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

300m

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

273 m

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

## The correct option is D 273 mLet AB be the lighthouse and C and D be the positions of the ships. Then, AB = 100 m, ∠ ACB=30∘ and ∠ ADB 45∘ ABAC=tan 30∘ 1√3⇒AC=AB×√3=100×√3mABAD=tan 45∘=1⇒AD=AB=100 mSo,CD=(AC+AD)=(100√3+100) =100(√3+1) =(100×2.73) =273 m

Suggest Corrections
0
Join BYJU'S Learning Program
Related Videos
Questions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program