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Question

Two slabs of same thickness 1 cm each are placed as shown.

Find the refractive index of a slab of thickness 3 cm which will produce the same normal shift in position of object (O), as produced by combination of slabs.

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Solution

Let μeq be the R.I of slab of thickness t=3 cm
Snet=S1+S2
or t(11μeq)=t1(11μ1)+t2(11μ2)
3(11μeq)=1(123)+1(112)
3(11μeq)=13+12=56
or, 11μeq=518
or, 1μeq=1518=1318
μeq=1813=1.38
Why this question?

Caution: The formula μeq=2μ1μ2μ1μ2 is only applicable when sum of thickness of two slabs is equal to thickness of equivalent slab.

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