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Two slits spaced 0.25 mm apart are placed at 0.75 m from a screen and illuminated by coherent light with a wavelength of 650 nm.  The intensity at the centre of the central maximum (θ=0) is I0.  The distance on the screen from the centre of central maximum to the point where the intensity has fallen to I02 is nearly
  1. 25 mm
  2. 0.4 mm
  3. 0.5 mm
  4. 0.1 mm


Solution

The correct option is C 0.5 mm
I=I0cos2(πd sinθ)λ=I02
cos(πd sinθλ)=12
we get,
x=λD4d=650×109×0.754×0.25×103=487.5×106m
=0.4875mm=0.5mm

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