Two small spheres each carrying a charge q are placed r metre apart. If one of the spheres is taken around the other one in a circular path, the work done will be equal to :

force between them

\times

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force between them

\times

π

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force between them / r

π

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zero

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Solution

The correct option is D zero
Potential energy between any two given particles
$= \frac{k q_{1} q_{2}}{r}$
since revolving in circle does not change the distance $r$ between these charges, change in P.E. will be equal to zero
hence
$w o r k$ $d o n e = 0$

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Two small spheres each carrying a charge q are placed r metre apart. If one of the spheres is taken around the other one in a circular path, the work done will be equal to :

The correct option is D zeroPotential energy between any two given particles=kq1q2rsince revolving in circle does not change the distance r between these charges, change in P.E. will be equal to zerohence work done=0

The correct option is D zero
Potential energy between any two given particles
$= \frac{k q_{1} q_{2}}{r}$
since revolving in circle does not change the distance $r$ between these charges, change in P.E. will be equal to zero
hence
$w o r k$ $d o n e = 0$