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Question

# Two soap bubbles in vacuum, of radius 3 cm and 4 cm coalesce to form a single bubble under isothermal conditions. Then the radius of bigger bubble is:

A
7 cm
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B
127 cm
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C
12 cm
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D
5 cm
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Solution

## The correct option is D 5 cmFor isothermal conditions, Boyle's law holds good. P1V1+P2V2=PVwhere P1= excess pressure inside first bubble P2= excess pressure inside second bubble V1= volume of first bubble V2= volume of second bubble P= excess pressure of new bubble formed V= volume of new bubble formedP1V1+P2V2=PV⇒4Tr1×43πr31+4Tr2×43πr32=4TR×43πR3⇒R=√r21+r22=√32+42=5cm

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