Two solid compounds X and Y dissociates at a certain temperature as follows- Xs- Ag-2Bg- K P 1 - 9- 10 -3 atm 3 Ys- 2Bg-Cg- K P 2 - 4-5- 10 -3 atm 3The total pressure of gases over a mixture of X and Y is-

The correct option is B 0.45 atm X(s)⇌ A(g)+2B(g); K _ P _ 1 = 9× 10 ^ 3 atm ^ 3 #160; ......(1) Y(s)⇌ 2B(g)+C(g); K _ P _ 2 = 4.5× 10 ^ ...

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Standard XII

Chemistry

Degree of Dissociation

Two solid com...

Question

Two solid compounds $X$ and $Y$ dissociates at a certain temperature as follows:
$X (s) ⇌ A (g) + 2 B (g); K_{P_{1}} = {9 \times 10}^{- 3} {a t m}^{3}$
$Y (s) ⇌ 2 B (g) + C (g); K_{P_{2}} = {4.5 \times 10}^{- 3} {a t m}^{3}$
The total pressure of gases over a mixture of $X$ and $Y$ is:

4.5

atm

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0.45

atm

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0.6

atm

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None of these

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Solution

The correct option is B $0.45$ atm
$X (s) ⇌ A (g) + 2 B (g); K_{P_{1}} = {9 \times 10}^{- 3} {a t m}^{3}$ ......(1)
$Y (s) ⇌ 2 B (g) + C (g); K_{P_{2}} = {4.5 \times 10}^{- 3} {a t m}^{3}$ ......(2)
Add reactions (1) and (2)
$X (s) + Y (s) ⇌ A (g) + 4 B (g) + C (g)$
$K_{P} = K_{P_{1}} \times K_{P_{2}} = {9 \times 10}^{- 3} {a t m}^{3} \times {4.5 \times 10}^{- 3} {a t m}^{3}$
Let P be the pressure of A.
The pressures of B and C will be 4P and P respectively.
Hence, the expression for the equilibrium constant will be $K_{P} = P_{A} \times P_{B}^{4} \times P_{C}$
Substitute values in the above expression.
$P \times (4 P)^{4} \times P = 9 \times 4.5 \times 10^{- 3} \times 10^{- 3}$
$P = 0.0735$
$6 P = 6 \times 0.0735 = 0.45 a t m$
Hence, the total pressure of gases over a mixture of X and Y is 0.45 atm.

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Two solid compounds X and Y dissociates at a certain temperature as follows:X(s)⇌A(g)+2B(g);KP1=9×10−3atm3Y(s)⇌2B(g)+C(g);KP2=4.5×10−3atm3The total pressure of gases over a mixture of X and Y is:

Two solid compounds $X$ and $Y$ dissociates at a certain temperature as follows:
$X (s) ⇌ A (g) + 2 B (g); K_{P_{1}} = {9 \times 10}^{- 3} {a t m}^{3}$
$Y (s) ⇌ 2 B (g) + C (g); K_{P_{2}} = {4.5 \times 10}^{- 3} {a t m}^{3}$
The total pressure of gases over a mixture of $X$ and $Y$ is: