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Standard XII

Chemistry

Osmotic Pressure

Two solutions...

Question

Two solutions of glucose have osmotic pressures 1.5 and 2.5 atm. 1 litre of first solution is mixed with 2 litre of second solution. The osmotic pressure of the resultant solution will be:

1.62 atm

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6.12 atm

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1.26 atm

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2.16 atm

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Solution

The correct option is D 2.16 atm
$π_{1} V_{1} + π_{2} V_{2} = π_{R} (V_{1} + V_{2})$
$1.5 \times 1 + 2.5 \times 2 = π_{R} \times 3$
$π_{R} = \frac{6.5}{3} = 2.16 a t m$

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Two solutions of glucose have osmotic pressures 1.5 and 2.5 atm. 1 litre of first solution is mixed with 2 litre of second solution. The osmotic pressure of the resultant solution will be:

The correct option is D 2.16 atmπ1V1+π2V2=πR(V1+V2)1.5×1+2.5×2=πR×3πR=6.53=2.16atm

The correct option is D 2.16 atm
$π_{1} V_{1} + π_{2} V_{2} = π_{R} (V_{1} + V_{2})$
$1.5 \times 1 + 2.5 \times 2 = π_{R} \times 3$
$π_{R} = \frac{6.5}{3} = 2.16 a t m$