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Question

Two sound sources each emitting sound of wavelength λ are fixed some distance apart. A listener moves with a velocity u along the line joining the two sources. The number of beats heard by him per second is

A
2uλ
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B
uλ
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C
u3λ
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D
2λu
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Solution

The correct option is A 2uλ
Number of extra waves receives from each side, n=±uλ
where,

u= speed of the observer

λ= Wavelength of sound

The number of beats is given by the difference between the number of extra
waves received on either sides

So,

Number of beats =uλ(uλ)=2uλ

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