Question

Two springs have their force constant as $$k_1$$ and $$k_2 (k_1 > k_2)$$. when they are stretched by the same force

A
no work is done in case of both the springs
B
equal work is done in case of both the springs
C
more work is done in case of second spring
D
more work is done in case of first spring

Solution

The correct option is C more work is done in case of second spring$$W=\frac{F^2}{2k}$$If both springs are stretched by same force then$$W \propto \frac{1}{k}.$$As $$k_1 > k_2$$ therefore, $$W_1 < W_2$$ ie; more work is done in case of second spring.Physics

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