    Question

# Two square have sides x cm and (x+4) cm. The sum of their areas is 656cm2. Find the sides of the squares.

A
8 cm, 12 cm
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B
12 cm, 15 cm
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C
6 cm, 10 cm
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D
16 cm, 20 cm
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Solution

## The correct option is C 16 cm, 20 cmArea of 1st square =x2Area of 2nd square =(x+4)2=x2+8x+16 Sum of areas = x2+x2+8x+16=656Simplifying and subtracting 656 from both sides 2x2+8x−640=0x2+4x−320=0 This is a standard quadratic equation of the form ax2+bx+c=0 with a=1,b=4 and c=−320. Solving it we get the values of x as x=16 or x=−20 Since x cannot be negative, x=16 So, side of 1st square = 16 and side of second square = 20  Suggest Corrections  0      Similar questions  Related Videos   Solving an Equation
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