Question

# Two stones are thrown vertically upwards simultaneously from the same point on the ground with initial speeds u1=30 m/sec and u2=50 m/sec. Which of the curves represents correct variation (for the time interval in which both reach the ground) of (x2−x1)= the relative position of second stone with respect to first with time (t). (v2−v1)= the relative velocity of second stone with respect to first with time (t). Assume that stones do not rebound after hitting the ground

A
A
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B
B
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C
C
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D
D
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Solution

## The correct option is D DWhile both the stones are in flight, a1=g and a2=g So arel=0⇒Vrel= constant ⇒xrel=(const)t ⇒ Curve of xrel vs t will be straight line till a stone hits the ground. After the first particle drops on ground, the separation (xrel) will decrease parabolically (due to gravitational acceleration), and finally becomes zero. and vrel= slope of xrel w.r.t. time.

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