Question

Two stones are thrown vertically upwards simultaneously from the same point on the ground with initial speeds u1=30 m/sec and u2=50 m/sec. Which of the curves represents correct variation (for the time interval in which both reach the ground) of

(x2−x1)= the relative position of second stone with respect to first with time (t).

(v2−v1)= the relative velocity of second stone with respect to first with time (t).

Assume that stones do not rebound after hitting the ground

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Solution

The correct option is **D** D

While both the stones are in flight, a1=g and a2=g

So arel=0⇒Vrel= constant

⇒xrel=(const)t

⇒ Curve of xrel vs t will be straight line till a stone hits the ground.

After the first particle drops on ground, the separation (xrel) will decrease parabolically (due to gravitational acceleration), and finally becomes zero.

and vrel= slope of xrel w.r.t. time.

While both the stones are in flight, a1=g and a2=g

So arel=0⇒Vrel= constant

⇒xrel=(const)t

⇒ Curve of xrel vs t will be straight line till a stone hits the ground.

After the first particle drops on ground, the separation (xrel) will decrease parabolically (due to gravitational acceleration), and finally becomes zero.

and vrel= slope of xrel w.r.t. time.

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