Two substances of densities $d_{1}$ and $d_{2}$ are mixed in equal volume and the relative density of mixture is 4. When they are mixed in equal masses, the relative density of mixture is 3. Then $d_{1} =$ ________ $\frac{g m}{c c}$ .

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Solution

The correct option is A 6
If $V_{1} = V_{2}$ R.d = $\frac{d_{1} + d_{2}}{2} = 4$
If $m_{1} = m_{2}$ R.d = $\frac{2 d_{1} d_{2}}{d_{1} + d_{2}} = 3$
$\Rightarrow$ $d_{1} d_{2} = 12$ $d_{1} + d_{2} = 8$
$\Rightarrow$ $d_{1}$ and $d_{2}$ are 6 and 2

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Two substances of densities d1 and d2 are mixed in equal volume and the relative density of mixture is 4. When they are mixed in equal masses, the relative density of mixture is 3. Then d1= ________ gmcc.

The correct option is A 6If V1=V2 R.d = d1+d22=4 If m1=m2 R.d = 2d1d2d1+d2=3 ⇒ d1d2=12 d1+d2=8 ⇒ d1 and d2 are 6 and 2

Two substances of densities $d_{1}$ and $d_{2}$ are mixed in equal volume and the relative density of mixture is 4. When they are mixed in equal masses, the relative density of mixture is 3. Then $d_{1} =$ ________ $\frac{g m}{c c}$ .

The correct option is A 6
If $V_{1} = V_{2}$ R.d = $\frac{d_{1} + d_{2}}{2} = 4$
If $m_{1} = m_{2}$ R.d = $\frac{2 d_{1} d_{2}}{d_{1} + d_{2}} = 3$
$\Rightarrow$ $d_{1} d_{2} = 12$ $d_{1} + d_{2} = 8$
$\Rightarrow$ $d_{1}$ and $d_{2}$ are 6 and 2