Two successive resonance frequencies in an open organ pipe are 1944 and 2592 $Hz$ . Find the length of the tube. The speed of sound in air is $324 {ms}^{- 1}$ .

25 cm

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50 cm

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12.5 cm

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None of these

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Solution

The correct option is A $25 cm$
$f_{0} = 2592 - 1944 = 648 Hz$
$λ = \frac{v}{f} = \frac{324}{648} = \frac{1}{2} m$
or $l = \frac{λ}{2} = 25 cm$

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Two successive resonance frequencies in an open organ pipe are 1944 and 2592 Hz. Find the length of the tube. The speed of sound in air is 324 ms−1.

The correct option is A 25 cmf0=2592−1944=648 Hz λ=vf=324648=12 m or l=λ2=25 cm

Two successive resonance frequencies in an open organ pipe are 1944 and 2592 $Hz$ . Find the length of the tube. The speed of sound in air is $324 {ms}^{- 1}$ .

The correct option is A $25 cm$
$f_{0} = 2592 - 1944 = 648 Hz$
$λ = \frac{v}{f} = \frac{324}{648} = \frac{1}{2} m$
or $l = \frac{λ}{2} = 25 cm$