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Question

Two thin discs each of mass 4.0 kg and radius 0.4 m are attached as shown in figure to form a rigid body. What is the rotational inertia of this body about an axis perpendicular to the plane of disc B and passing through its center?


A

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B

3.2kg - m2

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C

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D

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Solution

The correct option is B

3.2kg - m2


IB = I of disc B about centre of mass + I of disc A about centre of mass + mass of disc A × (distance between centres of A and B)2

= mR22 + mR22 + m(2R)2 = 5mR2 = 5×4×(0.4)2 = 3.2 kgm2


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