You visited us 1 times! Enjoying our articles? Unlock Full Access!

Power and Thin Lenses in Contact

Two thin lens...

Question

Two thin lenses of focal; lengths $f_{1}$ and $f_{2}$ are in contact and coaxial. The combination is equivalent to a single lens of power

f_{1} + f_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{f_{1} f_{2}}{f_{1} + f_{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{1}{2} (f_{1} + f_{2})

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{f_{1} + f_{2}}{f_{1} f_{2}}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $\frac{f_{1} + f_{2}}{f_{1} f_{2}}$
As we know,
$P = \frac{1}{F} = \frac{f_{1} + f_{2}}{f_{1} f_{2}}$

Suggest Corrections

Similar questions

Two thin lenses of focal lengths $f_{1}$ and $f_{2}$ are placed in contact with each other. The focal length of the combination will be given by:

If two thin lenses of focal length f₁ and f₂ are held in contact then the focal length of the combination will be

f_{1}

f_{2}

f_{1} a n d f_{2}

d < f_{1}, d < f_{2}

Δ

f_{1}

f_{2}

\frac{1}{f} = \frac{1}{f_{1}} + \frac{1}{f_{2}}

Join BYJU'S Learning Program