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Question

Two thin long parallel wires separated by a distance 'b' are carrying a current i A each. The magnitude of the force per unit length exerted by one wire on the other is?

A
μoi2b2
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B
μoi22πb
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C
μoi2πb
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D
μoi2πb2
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Solution

The correct option is A μoi22πb
Given, distance between two parallel wires=b and current flowing in both the wire=i
Now we know force of attraction between two parallel current carrying conductors is given by
F=μ2I1I2l4πb---------(A)
HereI1=I2 as per question,
Thus equation A reduces to
Fl=μ0i22πb

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