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Question

Two trains, each moving with a velocity of 30ms−1, cross each other. One of the trains gives a whistle whose frequency is 600Hz. If the speed of sound is 330ms−1, the apparent frequency for passengers sitting in the other train before crossing would be

A
600Hz
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B
630Hz
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C
920Hz
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D
720Hz
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Solution

The correct option is D 720Hz
Here, velocity of source vS=30ms1vS=30ms−1
velocity of observer vO=30ms1vO=30ms−1
velocity of sound v=330ms1;υ=660Hzv=330ms−1;υ=660Hz
as source and observer are moving towards each other with same speed, therefore apparent frequency is
υ=υ[v+vOv+vS]=600[330+3033030]=720Hz

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