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Question

Two vectors are given by $$\vec a =  - 2\hat i + \hat j - 3\hat k$$ and $$\vec b =  - 5\hat i + 3\hat j - 2\hat k$$. If $$3\vec a + 2\vec b - \vec c = 0$$ then third


Solution

Given $$\vec{a}=-2\hat{i}+\hat{j}-3\hat{k}$$
$$\vec{b}=-5\hat{i}+3\hat{j}-2{k}$$
as per question $$3\vec{a}+2\vec{b}-\vec{c}=0$$
$$-6\hat{i}+3\hat{j}-9\hat{k}-10\hat{i}+6\hat{j}-4\hat{k}-\vec{c}=0$$
$$vec{c}=-16\hat{i}+9\hat{j}-13\hat{k}$$

Physics

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