Question

# Two vectors are given by $$\vec a = - 2\hat i + \hat j - 3\hat k$$ and $$\vec b = - 5\hat i + 3\hat j - 2\hat k$$. If $$3\vec a + 2\vec b - \vec c = 0$$ then third

Solution

## Given $$\vec{a}=-2\hat{i}+\hat{j}-3\hat{k}$$$$\vec{b}=-5\hat{i}+3\hat{j}-2{k}$$as per question $$3\vec{a}+2\vec{b}-\vec{c}=0$$$$-6\hat{i}+3\hat{j}-9\hat{k}-10\hat{i}+6\hat{j}-4\hat{k}-\vec{c}=0$$$$vec{c}=-16\hat{i}+9\hat{j}-13\hat{k}$$Physics

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