Two vectors A- and B- as such that A- - B- - A- - B- Then

The correct option is A A⃗ . B⃗ = 0 Given A + B = A B ⇒| A + B #160; | =| A B #160; | ⇒| A + B #160; | #160; ^ 2 = ...

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Test for Collinearity of Vectors

Two vectors ...

Question

Two vectors $\to A$ and $\to B$ as such that $\to A + \to B = \to A - \to B$ . Then

\to A . \to B = 0

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\to A \times \to B = 0

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\to A = 0

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\to B = 0

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Solution

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Similar questions

\to a

\to b

\to a \cdot \to b < 0

| \to a \cdot \to b | = | \to a \times \to b |

\to a

\to b

\to A

\to B

| \to A + \to B | = | \to A - \to B |

\to A

\to B

\to a, \to b, \to c

\to a + \to b + \to c = \to 0,

\to a \times \to b = \to b \times \to c = \to c \times \to a,

[\to a \to b \to c] = 0.

\to A

\to B

(\to A + \to B) ⊥ (\to A - \to B)

\to a, \to b, \to c

\to a . \to b = \to a . \to c, \to a \times \to b = \to a \times \to c, \to a \neq 0

\to b = \to c

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