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Question

Two waves, each having a frequency of 100 Hz and a wavelength of 2.0 cm, are travelling in the same direction on a string. What is the phase difference between the waves (a) if the second wave was produced 0.015 s later than the first one at the same place, what would be the resultant amplitude? [Given individual amplitudes = 2.0 mm]

A

4 mm

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B

2 mm

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C

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D

zero

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Solution

The correct option is D

zero


Phase diagram method can be used here but for that we need to calculate the phase difference.

Δϕ=2πΔtT

Here Δt=0.015 s

T1 which is the time period =1f

T=1100

So Δϕ=2π0.0151100=3π=2π+π as 2π is the period, the effective phase difference is π now let's draw

the phase diagram

So we can see that net amplitude would be zero.


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