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Question

Two waves
y1=A1sin(ωtβ1) and
y2=A2sin(ωtβ2)
superimpose to form a resultant wave whose amplitude is

A
A21+A22+2A1A2cos(β1β2)
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B
A21+A22+2A1A2sin(β1β2)
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C
A1+A2
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D
|A1+A1|
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Solution

The correct option is D A21+A22+2A1A2cos(β1β2)
The phase difference the two waves y1 and y2, δ=|β1β2|
Amplitude of the wave y1 and y2 is A1 and A2 respectively.
Thus resultant amplitude R=A21+A22+2A1A2cosδ
R=A21+A22+2A1A2cos|β1β2|

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