Two waves y1 - A1sin - t - - 1y2 - A2sin - t - - 2 superimpose to form a resultant wave whose amplitude is

The correct option is A √(A_1^2 + A_2^2 + 2A_1A_2cos (β _1 β _2)) y=y_1 +y_2 y=A #160;Sin #160;(wt #160; #160;β) A=√(A_1^2 ...

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Wave Equation

Two waves y...

Question

Two waves $y_{1} = A_{1} sin (ω t - β_{1}) y_{2} = A_{2} sin (ω t - β_{2})$ superimpose to form a resultant wave whose amplitude is

\sqrt{A_{1}^{2} + A_{2}^{2} + 2 A_{1} A_{2} cos (β_{1} - β_{2})}

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\sqrt{A_{1}^{2} + A_{2}^{2} + 2 A_{1} A_{2} sin (β_{1} - β_{2})}

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A_{1} + A_{2}

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| A_{1} + A_{2} |

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Solution

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Similar questions

y_{1} = A_{1} s i n (ω t - β_{1}), y_{2} = A_{2} s i n (ω t - β_{2})

y_{1} = A_{1} sin (ω t - β_{1})

y_{2} = A_{2} sin (ω t - β_{2})

A particle is subjected to two simple harmonic motions given as $x_{1} = A_{1} s i n ω t$ and $x_{2} = A_{2} s i n (ω t + \frac{π}{3})$

Find A. the displacement at t = 0

B. the maximum speed of the particle and

C. the maximum acceleration of the particle

x_{1} = A_{1} s i n ω t

x_{2} = A_{2} (ω t + \frac{π}{4})

a_{1}, a_{2}, a_{3}, a_{4}

a_{1}^{2} + a_{2}^{2} + a_{3}^{2} + a_{4}^{2} = 1

(a_{1} - a_{2})^{2} + (a_{2} - a_{2})^{2} + (a_{3} - a_{4})^{2} + (a_{4} - a_{1})^{2}

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