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Question

Two wires $$A$$ and $$B$$ of same dimensions are stretched by same amount of force. Young's modulus of $$A$$ is twice that of $$B$$. Which wire will get more elongation? Enter 1 for A and 2 for B.


Solution

Youmng's modulus $$\displaystyle =\frac{longitudinal \  stress}{longitudinal  \  strain}$$
i.e, $$\displaystyle Y=\frac{F/A}{\Delta l /l}$$
$$\displaystyle \Delta l=\frac{Fl}{AY}$$
$$\therefore \Delta l \propto \frac{1}{Y}$$
As $$Y_A=2Y_B$$  so B has more elongation $$(\Delta l)$$

Physics

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