Question

Two wires are 12 m and 16 m long. The wires are to be cut into pieces of equal length. Find the maximum length of each piece.

Answer 1

Required number is the HCF of 12 and 16.

$12=2\times 2\times 3$

$16=2\times 2\times 2\times 2$

$\text{Required HCF}=2\times 2$

HCF of 12 and 16 is 4

$\therefore \text{The maximum length of each piece is 4 m.}$