Two wires of same diameter of the same material having the length l and 2l. If the force F is applied on each, the ratio of the work done in the two wires will be

1 : 2

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1 : 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
1 : 2

$W = \frac{1}{2} F e a n d e \propto l ∴ W \propto l$ (F is constant)

$∴ \frac{W_{1}}{W_{2}} = \frac{l_{1}}{l_{2}} = \frac{l}{2 l} = \frac{1}{2}$

Suggest Corrections

Similar questions

Q. Two wires of same diameter and made of the same material are having the length

1 m

and

2 m

. If the force

F

is applied on each end of the wires, the ratio of the work done in the two wires will be

Two wires of same diameter of the same material having the length l and 2l. If the force F is applied on each, the ratio of the work done in the two wires will be

Q. Two wires of the same diameter of the same material having the length

ℓ

and

2 ℓ

. If the force is applied on each, the ratio of the work done in the two will be

Two wires A and B of the same material have their lengths in the ratio of 1:2 and their diameters in the ratio of 2:1. If they are stretched with the same force, the ratio of the increase in the length of A to that of B will be

Q. Two wires A and B are made of same material. The wire A has a length l and diameter r while the wire B has a length 2l and diameter r/2. If the two wires are stretched by the same force, the elongation in A divided by the elongation in B is
(a) 1/8
(b) 1/4
(c) 4
(d) 8

Join BYJU'S Learning Program

Two wires of same diameter of the same material having the length l and 2l. If the force F is applied on each, the ratio of the work done in the two wires will be

The correct option is A 1 : 2 W=12Fe and e∝l∴ W∝l (F is constant) ∴W1W2=l1l2=l2l=12

The correct option is A
1 : 2

$W = \frac{1}{2} F e a n d e \propto l ∴ W \propto l$ (F is constant)

$∴ \frac{W_{1}}{W_{2}} = \frac{l_{1}}{l_{2}} = \frac{l}{2 l} = \frac{1}{2}$