Two wires of the same diameter and of the same material have the length l and 2l. If the force F is applied on each, the ratio of the work done in the two wires will be
A
1:2
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B
1:4
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C
1:1
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D
2:1
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Solution
The correct option is A 1:2 Given,
Length of the first wire, l1=l
Length of the second wire, l2=2l
As given, force for both wires is same. Therefore, work done is directory proportional to length of wire.
Hence, W=12Fl Wαl W1W2=l1l2=l2l=12