Types of bonding $N H_{4} C l$ are ionic (between $N H_{4}^{+}$ and $C l^{-}$ ), covalent (between N and H) and coordinate (between $H^{+}$ and $N H_{3}$ ).
If true enter 1, else enter 0.
1

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Solution

The correct option is A 1
Electron sharing between N and H while electron donation between CL- and NH4+

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B_{2} H_{6}

Identify the correct statement(s)

A. All N - H bonds in $N H_{4}^{+}$ ion are identical after the formation

B. Formal charge of H and Cl in HCl are +1 and - 1 respecti

C. $[F e (C N)_{6}]^{- 4}$ ion has dative bonds but no ionic bonds

D. $N H_{4} C l$ contains ionic , covalent and dative bonds

N

C l

H

H - N - H

{N H}_{3}

H - A s - H

A s H_{3}

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