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Question

Ultraviolet light of wavelength λ=200 nm is used in an experiment on photoelectric effect with cesium (ϕ=1.8). Find De-Broglie wavelength of photo electron with maximum kinetic energy.


A
47×109m
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B

285×109m
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C
197×109m
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D
27×109m 
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Solution

The correct option is A 47×109m
KEmax=hvϕ
hν=1242200=6.21 eV
ϕ=1.8 eV
KEmax=6.211.8=4.41
=4.41 eV
λ=1.24.41 nm=1.22.1 nm=47×109 m
 

Physics

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